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x^2+x-2018=0
a = 1; b = 1; c = -2018;
Δ = b2-4ac
Δ = 12-4·1·(-2018)
Δ = 8073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8073}=\sqrt{9*897}=\sqrt{9}*\sqrt{897}=3\sqrt{897}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3\sqrt{897}}{2*1}=\frac{-1-3\sqrt{897}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3\sqrt{897}}{2*1}=\frac{-1+3\sqrt{897}}{2} $
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